What Happens If We Remove super() From a Child Constructor?
Ever tried to build a house without a foundation? Or maybe you’ve tried to order a "Double Cheeseburger" at a restaurant, only to realize the chef still needs to cook the "Burger" part first. In Ja...

Source: DEV Community
Ever tried to build a house without a foundation? Or maybe you’ve tried to order a "Double Cheeseburger" at a restaurant, only to realize the chef still needs to cook the "Burger" part first. In Java programming, inheritance works exactly like that. When you create a "Child" object, Java insists that the "Parent" part of that object is built first. But what happens if you forget to explicitly call super()? Let’s dive into the mechanics of the Java constructor chain and see how the compiler actually has your back. Core Concepts: The Invisible Safety Net In Java, every class (except Object) has a parent. When you instantiate a child class, the parent class’s constructor must run before the child’s constructor finishes. Here is the secret: If you don’t write super(), the Java compiler inserts it for you. Key Features & Use Cases The Default Behavior: If you omit super(), Java automatically adds a no-argument super(); as the very first line of your child constructor. The "Must-Have" Ru